If we ignore the cosmological constant contribution, for each of the 10 non-zero components of the Ricci curvature tensor, the sum of the component of the Ricci curvature tensor minus half of the corresponding component of the metric tensor multiplied by the Ricci scalar is equal to four times the ratio of the circumference of an arbitrary circle divided by its radius, multiplied by Newton's gravitational constant divided by the fourth power of the speed of light in vacuum and multiplied by the corresponding component of the stress-energy tensor.
Would this be clearer than the original [http://en.wikipedia.org/wiki/Einstein_field_equations]? After all, I don't use any weird symbols and avoid greek letters... Surely the author of that blog post would be satisfied by this ... Perhaps, I should include what I mean by Ricci curvature tensor ... but first define what I mean by a tensor, including the metric tensor, and explain other words like stress-energy tensor; it should not take more than a few lines of text for it to be completely clear, right?
Would this be clearer than the original [http://en.wikipedia.org/wiki/Einstein_field_equations]? After all, I don't use any weird symbols and avoid greek letters... Surely the author of that blog post would be satisfied by this ... Perhaps, I should include what I mean by Ricci curvature tensor ... but first define what I mean by a tensor, including the metric tensor, and explain other words like stress-energy tensor; it should not take more than a few lines of text for it to be completely clear, right?