Yes, but integers are a specialization of polynomials. For example, the number 263 can be written as 2x^2 + 6x + 3, where x=10.
(Note that for integers, a post-processing step is necessary to account for coefficients that are larger than the number base, but I guess this is relatively inexpensive).
Indeed, having a fast way to multiply in Z[x] gives you a fast way to multiply in Z and vice versa. In the reverse direction, you can encode the polynomial f = 2x^2 + 6x + 3 as 30602, and 30602^2 = 936482404 tells you that f^2 = 4x^4 + 24x^3 + 48x^2 + 36x + 9 (of course, on a computer you do this in binary as opposed to decimal).
This correspondence is often exploited in both directions. If you ask a sufficiently sophisticated computer algebra system (SageMath, for example) to multiply two large polynomials with integer or rational coefficients, chances are that it will reduce the problem to multiplying two large integers, then reduce that problem to multiplying two large polynomials (but different from the ones you started with), and then proceed using recursive polynomial and integer multiplications to compute that product... (i.e. going through a sequence of transformations Z[x] -> Z -> Z[x] -> ...)
(Note that for integers, a post-processing step is necessary to account for coefficients that are larger than the number base, but I guess this is relatively inexpensive).